Integrand size = 20, antiderivative size = 89 \[ \int (c+d x)^2 \cos (a+b x) \sin (a+b x) \, dx=-\frac {c d x}{2 b}-\frac {d^2 x^2}{4 b}+\frac {d (c+d x) \cos (a+b x) \sin (a+b x)}{2 b^2}-\frac {d^2 \sin ^2(a+b x)}{4 b^3}+\frac {(c+d x)^2 \sin ^2(a+b x)}{2 b} \]
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Time = 0.06 (sec) , antiderivative size = 89, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {4489, 3391} \[ \int (c+d x)^2 \cos (a+b x) \sin (a+b x) \, dx=-\frac {d^2 \sin ^2(a+b x)}{4 b^3}+\frac {d (c+d x) \sin (a+b x) \cos (a+b x)}{2 b^2}+\frac {(c+d x)^2 \sin ^2(a+b x)}{2 b}-\frac {c d x}{2 b}-\frac {d^2 x^2}{4 b} \]
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Rule 3391
Rule 4489
Rubi steps \begin{align*} \text {integral}& = \frac {(c+d x)^2 \sin ^2(a+b x)}{2 b}-\frac {d \int (c+d x) \sin ^2(a+b x) \, dx}{b} \\ & = \frac {d (c+d x) \cos (a+b x) \sin (a+b x)}{2 b^2}-\frac {d^2 \sin ^2(a+b x)}{4 b^3}+\frac {(c+d x)^2 \sin ^2(a+b x)}{2 b}-\frac {d \int (c+d x) \, dx}{2 b} \\ & = -\frac {c d x}{2 b}-\frac {d^2 x^2}{4 b}+\frac {d (c+d x) \cos (a+b x) \sin (a+b x)}{2 b^2}-\frac {d^2 \sin ^2(a+b x)}{4 b^3}+\frac {(c+d x)^2 \sin ^2(a+b x)}{2 b} \\ \end{align*}
Time = 0.22 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.56 \[ \int (c+d x)^2 \cos (a+b x) \sin (a+b x) \, dx=\frac {\left (d^2-2 b^2 (c+d x)^2\right ) \cos (2 (a+b x))+2 b d (c+d x) \sin (2 (a+b x))}{8 b^3} \]
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Time = 0.35 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.78
method | result | size |
risch | \(-\frac {\left (2 x^{2} d^{2} b^{2}+4 b^{2} c d x +2 b^{2} c^{2}-d^{2}\right ) \cos \left (2 x b +2 a \right )}{8 b^{3}}+\frac {d \left (d x +c \right ) \sin \left (2 x b +2 a \right )}{4 b^{2}}\) | \(69\) |
parallelrisch | \(\frac {-b^{2} x d \left (\frac {d x}{2}+c \right ) \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{4}-2 b d \left (d x +c \right ) \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{3}+\left (\left (3 x^{2} d^{2}+6 c d x +4 c^{2}\right ) b^{2}-2 d^{2}\right ) \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{2}+2 b d \left (d x +c \right ) \tan \left (\frac {a}{2}+\frac {x b}{2}\right )-b^{2} x d \left (\frac {d x}{2}+c \right )}{2 b^{3} \left (1+\tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{2}\right )^{2}}\) | \(138\) |
derivativedivides | \(\frac {-\frac {a^{2} d^{2} \cos \left (x b +a \right )^{2}}{2 b^{2}}+\frac {a c d \cos \left (x b +a \right )^{2}}{b}-\frac {2 a \,d^{2} \left (-\frac {\left (x b +a \right ) \cos \left (x b +a \right )^{2}}{2}+\frac {\cos \left (x b +a \right ) \sin \left (x b +a \right )}{4}+\frac {x b}{4}+\frac {a}{4}\right )}{b^{2}}-\frac {c^{2} \cos \left (x b +a \right )^{2}}{2}+\frac {2 c d \left (-\frac {\left (x b +a \right ) \cos \left (x b +a \right )^{2}}{2}+\frac {\cos \left (x b +a \right ) \sin \left (x b +a \right )}{4}+\frac {x b}{4}+\frac {a}{4}\right )}{b}+\frac {d^{2} \left (-\frac {\left (x b +a \right )^{2} \cos \left (x b +a \right )^{2}}{2}+\left (x b +a \right ) \left (\frac {\cos \left (x b +a \right ) \sin \left (x b +a \right )}{2}+\frac {x b}{2}+\frac {a}{2}\right )-\frac {\left (x b +a \right )^{2}}{4}-\frac {\sin \left (x b +a \right )^{2}}{4}\right )}{b^{2}}}{b}\) | \(215\) |
default | \(\frac {-\frac {a^{2} d^{2} \cos \left (x b +a \right )^{2}}{2 b^{2}}+\frac {a c d \cos \left (x b +a \right )^{2}}{b}-\frac {2 a \,d^{2} \left (-\frac {\left (x b +a \right ) \cos \left (x b +a \right )^{2}}{2}+\frac {\cos \left (x b +a \right ) \sin \left (x b +a \right )}{4}+\frac {x b}{4}+\frac {a}{4}\right )}{b^{2}}-\frac {c^{2} \cos \left (x b +a \right )^{2}}{2}+\frac {2 c d \left (-\frac {\left (x b +a \right ) \cos \left (x b +a \right )^{2}}{2}+\frac {\cos \left (x b +a \right ) \sin \left (x b +a \right )}{4}+\frac {x b}{4}+\frac {a}{4}\right )}{b}+\frac {d^{2} \left (-\frac {\left (x b +a \right )^{2} \cos \left (x b +a \right )^{2}}{2}+\left (x b +a \right ) \left (\frac {\cos \left (x b +a \right ) \sin \left (x b +a \right )}{2}+\frac {x b}{2}+\frac {a}{2}\right )-\frac {\left (x b +a \right )^{2}}{4}-\frac {\sin \left (x b +a \right )^{2}}{4}\right )}{b^{2}}}{b}\) | \(215\) |
norman | \(\frac {\frac {\left (2 b^{2} c^{2}-d^{2}\right ) \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{2}}{b^{3}}+\frac {c d \tan \left (\frac {a}{2}+\frac {x b}{2}\right )}{b^{2}}+\frac {d^{2} x \tan \left (\frac {a}{2}+\frac {x b}{2}\right )}{b^{2}}-\frac {d^{2} x^{2}}{4 b}-\frac {c d \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{3}}{b^{2}}-\frac {c d x}{2 b}-\frac {d^{2} x \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{3}}{b^{2}}+\frac {3 d^{2} x^{2} \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{2}}{2 b}-\frac {d^{2} x^{2} \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{4}}{4 b}+\frac {3 c d x \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{2}}{b}-\frac {c d x \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{4}}{2 b}}{\left (1+\tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{2}\right )^{2}}\) | \(218\) |
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Time = 0.25 (sec) , antiderivative size = 92, normalized size of antiderivative = 1.03 \[ \int (c+d x)^2 \cos (a+b x) \sin (a+b x) \, dx=\frac {b^{2} d^{2} x^{2} + 2 \, b^{2} c d x - {\left (2 \, b^{2} d^{2} x^{2} + 4 \, b^{2} c d x + 2 \, b^{2} c^{2} - d^{2}\right )} \cos \left (b x + a\right )^{2} + 2 \, {\left (b d^{2} x + b c d\right )} \cos \left (b x + a\right ) \sin \left (b x + a\right )}{4 \, b^{3}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 175 vs. \(2 (78) = 156\).
Time = 0.25 (sec) , antiderivative size = 175, normalized size of antiderivative = 1.97 \[ \int (c+d x)^2 \cos (a+b x) \sin (a+b x) \, dx=\begin {cases} \frac {c^{2} \sin ^{2}{\left (a + b x \right )}}{2 b} + \frac {c d x \sin ^{2}{\left (a + b x \right )}}{2 b} - \frac {c d x \cos ^{2}{\left (a + b x \right )}}{2 b} + \frac {d^{2} x^{2} \sin ^{2}{\left (a + b x \right )}}{4 b} - \frac {d^{2} x^{2} \cos ^{2}{\left (a + b x \right )}}{4 b} + \frac {c d \sin {\left (a + b x \right )} \cos {\left (a + b x \right )}}{2 b^{2}} + \frac {d^{2} x \sin {\left (a + b x \right )} \cos {\left (a + b x \right )}}{2 b^{2}} - \frac {d^{2} \sin ^{2}{\left (a + b x \right )}}{4 b^{3}} & \text {for}\: b \neq 0 \\\left (c^{2} x + c d x^{2} + \frac {d^{2} x^{3}}{3}\right ) \sin {\left (a \right )} \cos {\left (a \right )} & \text {otherwise} \end {cases} \]
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Leaf count of result is larger than twice the leaf count of optimal. 171 vs. \(2 (79) = 158\).
Time = 0.23 (sec) , antiderivative size = 171, normalized size of antiderivative = 1.92 \[ \int (c+d x)^2 \cos (a+b x) \sin (a+b x) \, dx=-\frac {4 \, c^{2} \cos \left (b x + a\right )^{2} - \frac {8 \, a c d \cos \left (b x + a\right )^{2}}{b} + \frac {4 \, a^{2} d^{2} \cos \left (b x + a\right )^{2}}{b^{2}} + \frac {2 \, {\left (2 \, {\left (b x + a\right )} \cos \left (2 \, b x + 2 \, a\right ) - \sin \left (2 \, b x + 2 \, a\right )\right )} c d}{b} - \frac {2 \, {\left (2 \, {\left (b x + a\right )} \cos \left (2 \, b x + 2 \, a\right ) - \sin \left (2 \, b x + 2 \, a\right )\right )} a d^{2}}{b^{2}} + \frac {{\left ({\left (2 \, {\left (b x + a\right )}^{2} - 1\right )} \cos \left (2 \, b x + 2 \, a\right ) - 2 \, {\left (b x + a\right )} \sin \left (2 \, b x + 2 \, a\right )\right )} d^{2}}{b^{2}}}{8 \, b} \]
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Time = 0.28 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.82 \[ \int (c+d x)^2 \cos (a+b x) \sin (a+b x) \, dx=-\frac {{\left (2 \, b^{2} d^{2} x^{2} + 4 \, b^{2} c d x + 2 \, b^{2} c^{2} - d^{2}\right )} \cos \left (2 \, b x + 2 \, a\right )}{8 \, b^{3}} + \frac {{\left (b d^{2} x + b c d\right )} \sin \left (2 \, b x + 2 \, a\right )}{4 \, b^{3}} \]
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Time = 0.17 (sec) , antiderivative size = 100, normalized size of antiderivative = 1.12 \[ \int (c+d x)^2 \cos (a+b x) \sin (a+b x) \, dx=\frac {\cos \left (2\,a+2\,b\,x\right )\,\left (\frac {d^2}{4}-\frac {b^2\,c^2}{2}\right )}{2\,b^3}+\frac {d^2\,x\,\sin \left (2\,a+2\,b\,x\right )}{4\,b^2}-\frac {d^2\,x^2\,\cos \left (2\,a+2\,b\,x\right )}{4\,b}+\frac {c\,d\,\sin \left (2\,a+2\,b\,x\right )}{4\,b^2}-\frac {c\,d\,x\,\cos \left (2\,a+2\,b\,x\right )}{2\,b} \]
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